Physics, asked by rahul42567383, 5 months ago

Calculate the work done in moving a charge of 2 c across 2 point having a potential difference of 12 v?

Answers

Answered by Anonymous

${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{ Charge\: (C) = 2\: coulomb}$

$\:\:\:\:\bullet\:\:\:\sf{ Potential\: difference\: (V) = 12 \:voltage}$

$\\$

${\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\$

$\:\:\:\:\bullet\:\:\:\sf{Work\: done \:?}$

$\\$

${\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\$

☯ As we know that,

$\\$

$\bigstar\:\: {\boxed{\sf{ V = \dfrac{J}{C} }}}$

$\\$

$\sf{Where,}$

$\:\:\:\:\bullet\:\:\:\sf{V = Voltage}$

$\:\:\:\:\bullet\:\:\:\sf{J = Work \:done}$

$\:\:\:\:\bullet\:\:\:\sf{C = Charge}$

$\\$

☯ Substituting the given values

$\\$

$\dashrightarrow\:\: \sf{ V = \dfrac{J}{C} }$

$\\$

$\dashrightarrow\:\: \sf{ V \times C = J }$

$\\$

$\dashrightarrow\:\: \sf{ J = 12 \times 2}$

$\\$

$\dashrightarrow\:\: \underline{\boxed{\sf{ _{}Work \: Done = 24 \:J^{}}}}$

Answered by samvartha

Answer:

V=W/Q

W=VQ

HERE, V=12V AND Q=2C

W=12X2

W=24J

HOPE IT HELPS YOU......

PLSSS MARK IT AS BRAINLIEST........

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