Question

Calculate the work done in moving a charge of 5 coulombs from a point at a potential of 29V to another point at 30V.

Answer 1

Q = 5C, V1 = 29V, V2 = 30V
V2 - V1 = W/Q
30 - 29 = W/5
1 = W/5
W = 5*1
W = 5J

Answer 2

$\rule{274}{2}$

Given the charge, q = 5 C

The initial potential at a point, V = 29 V.

The final potential at another point, v = 30 V

The relationship between work done, charge and change in potential difference is given as :-

$\bold{\sf{W=q\Delta V}}$

On substituting the given values, we get :-

$\sf{W=5C\times (30V-29V)}$

$\sf{W = 5 \times 1}\\\\\boxed{\sf{W = 5\ J}}$

$\rule{274}{2}$