Calculate the work done in moving a stationary charge Q from B to A, VA=200V,
VB=100V, Q=0.05C
Answers
Answered by
3
Answer:
5 j
Explanation:
given : q= 0.05
va= 200v
vb = 100v
as the electric field is an conservation
field ,thus the work done in moving a charge
from one point to another in path independent
therefore ,wba = q( va -vb) = 0.5(200-100)
answer = 5J
Answered by
0
Answer:
we know that -
Q(Va-Vb)
0.5(200-100)
0.5(100)
5J
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