Question

Calculate the work done in moving a stationary charge Q from B to A, VA=200V,

VB=100V, Q=0.05C​

Answer 1

Answer:

5 j

Explanation:

given : q= 0.05

va= 200v

vb = 100v

as the electric field is an conservation

field ,thus the work done in moving a charge

from one point to another in path independent

therefore ,wba = q( va -vb) = 0.5(200-100)

answer = 5J

Answer 2

Answer:

we know that -

Q(Va-Vb)

0.5(200-100)

0.5(100)

5J