Question

calculate the work done in raising a stone of mass 4kg and specific gravity 2 imerced in water from a depth of 3m to 1m below the surface

Answer 1

Can u tell me about specific gravity

Answer 2

Explanation:

specific gravity or relative density is defined as ratio of density of the object to ratio of density

of water

Hence,p/po=2

v be volume of the object

according tp archimedes principle

net weight of object=weight -buoyant force

=pvg-povg

=pvg(1-po/p)

=4×9.8×(1-1/2)

=mass of the object =4kg

=4×9.8×1/2

=18.6

hence workdone=weight ×distance

=18.6×2

=37.2joules