Question

calculate the work done in taking a charge of 0.02c from AtoB.if the potential at A is 20v and the potential at B is 30v.

Answer 1

Hi friend
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Your answer
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Charge (Q) = 0.02 C

Work done (W) = ?

Potential at point A = 20 V

Potential at point B = 30 V

So,
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Potential difference = (30 - 20) V = 10 V

We know,

V = W/Q

=> 10 = W/0.02

=> W = 10 × 0.02

=> W = 0.2 J

HOPE IT HELPS

Answer 2

Answer:

Given ,

Q= 0.02

potential at A = 20V

potential at B = 30V

potential difference = 30v-20v

= 10v

Now ,

V= W/Q

10= W/0.02

W= 10×0.02

W = 0.2 J Ans