Calculate the work done in the resistor of 20 ohm carrying 5A of current in 5 hours?
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Explanation:
here,R=20 ohm,I=5A
V=IR
potential difference (v) =100 volt
I=5A,T=5hours (5×60×60=1800seconds),Q=?
Q=IT
=5×1800
=9000 Coulomb
work done= 9000×100
=900000 joule
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