Calculate the work done on a nano car of mass 650 kg so as to increase its velocity from 18km h^-1 to 36km h^-1
sohildudhwalaoz5cz9:
It’s from chapter work and energy
No nonsense allowed
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Work done = Change in kinetic energy
=) W = 1/2 * m * {(v) ^2 - (u) ^2}
Given,
m= 650kg, u = 18 km/h = 18 * 1000 / 60*60 m/s
= 5 m/s and v = 36km/h = 36 * 1000 / 60*60m/s
= 10 m/s.
=) W = 1/2 * 650 * [(10)^2 - (5)^2] J
=) W = 1/2 * 650 * (100-25) J
=) W = 1/2 * 650 * 75 J
=) W = 24,375 J.
Hope it's helpful to u.
=) W = 1/2 * m * {(v) ^2 - (u) ^2}
Given,
m= 650kg, u = 18 km/h = 18 * 1000 / 60*60 m/s
= 5 m/s and v = 36km/h = 36 * 1000 / 60*60m/s
= 10 m/s.
=) W = 1/2 * 650 * [(10)^2 - (5)^2] J
=) W = 1/2 * 650 * (100-25) J
=) W = 1/2 * 650 * 75 J
=) W = 24,375 J.
Hope it's helpful to u.
Thanx
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