Calculate the work done required to stop a car of mass 1000kg moving at a velocity of 10 m/s will be
Answers
You are being asked to deploy this equation:
force = mass X acceleration, or f = m*a
m = 1000 kg
velocity 45 km/hr = 12.5 m/s so
acceleration a = -2.5 m/s^2 Therefore
f = m*a = 1000 * -2.5 = -2500 newtons
Answer:
Work done to stop the car is -50,000 J.
Explanation:
Mass of the car, m = 1000 Kg
The initial velocity of the car, u = 10 m/s
The car has been stopped. So its final velocity, v = 0 m/s
The initial kinetic energy of the car,
K.E₁ = (mu²) / 2
K.E₁ = (1000 × 10²) / 2
K.E₁ = 1,00,000 / 2
K.E₁ = 50,000 J
The final kinetic energy of the car will be zero since it has stopped the motion.
K.E₂ = 0 J
From the work-energy theorem, we know that the change in kinetic energy is equal to the work done.
∴ Work done to stop the car, W = Final K.E - Initial K.E
W = K.E₂ -K.E₁
W = 0 - 50000
W = -50,000 J