Question

can anyone plz help urgent needed​

Answer 1

Answer:

Q3) The width of the rectangle is 7 cm.

Q4) a) The perimeter of the rectangle is (2m+24)

cm.

b) The area of the rectangle is (7m+35) sq.cm

Step-by-step explanation:

Q3)

As given that the perimeter of the square and the rectangle is same;

The perimeter of the square is

4(11) cm

= 44 cm

Now let the width of the rectangle be w then,

2(l+w) = 44 cm

or, 2(15+w) = 44 cm

or, 30+2w = 44 cm

or, 2w = (44-30) cm

or, w = 14/2 cm

or, w = 7 cm.

Therefore, the width of the given rectangle is 7 cm.

Q4)

a) Perimeter of a rectangle

= 2(l+b)

= 2{(m+5)+7} cm

= 2{m+12}cm

= (2m+24) cm

Therefore, the perimeter of the rectangle is (2m+24) cm

b)Area of a rectangle

= (l×b)

={(m+5)×7} sq.cm

= (7m+35) sq.cm

Therefore, the area of the rectangle is (7m+35) sq.cm

Answer 2

Answer:

3).perimeter of square = 4s

P = 4×11 = 44cm

given perimeter of square = perimeter of rectangle

perimeter of rectangle = 2(l+b)

2(15+b) = 44

15+b = 22

b = 7

width of rectangle w = 7cm