calculate the work done to increase the radius of a soap bubble from 1cm to 3 cm surface tension of the solution is 0.025Nm-1. solutions
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as work done = st*change in area*2
change in area of a bubble is 4πr²-4πR²= 1.005m²
putting values in the above question
w= 0.025*1.005*2
.
0.0502J
change in area of a bubble is 4πr²-4πR²= 1.005m²
putting values in the above question
w= 0.025*1.005*2
.
0.0502J
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