Question

Calculate the work done to stop a 425 kg body that was moving at 2ms

Answer 1

Explanation,

Given,

• Mass of a body (m) = 425 kg
• Velocity (v) = 2 m/s

To Find,

• The work done by a body.

Solution,

According to the work and Energy theorem,

Work done = Kinetic energy

⇒ W = K.E

⇒ W = ¹/2 × mv²

[ Put the values ]

⇒ W = ¹/2 × 425 × 2²

⇒ W = ¹/2 × 425 × 4

⇒ W = 425 × 2

⇒ W = 850 J

Therefore,

The work done by a body is 850 J.

For information,

• P.E = mgh
• M.E = K.E + P.E
• W = F × s

Answer 2

$\huge\mathcal\colorbox{gold}{{\color{black}{★ANSWER★}}}$

$\huge\color{gold}{\textbf{\textsf{GIVEN :-}}}$

• Mass of body (m) = 425 kg
• Velocity (v) = 2 m/s

$\huge\color{gold}{\textbf{\textsf{TO FIND :-}}}$

• The work done by the body.

$\huge\color{gold}{\textbf{\textsf{SOLUTION :-}}}$

According to the work & energy theorem,

Work done = Kinetic energy

=> W = K.E

=> W = 1/2 × mv²

=> W = 1/2 × 425 × 2²

=> W = 1/2 × 425 × 4

=> W = 425 × 2

=> W = 850 J

Hence, the work done by the body is 850 J.

Hope it Helps Buddy ♥️