Question

find the three numbers of AP whose sum is 15 and product is - 55​

Answer 1

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Answer 2

Answer:

Let a + d, a, a - d are the three terms of AP according to the given question.

Sum of terms= 15

a + d + a + a - d =15

3a =15

a = 15/3

a =5

Product = -55

(a + d) × a × (a - d) = -55

(a^2 - d^2) × a = -55

(5^2 -d^2) × 5 = -55

25 - d^2 = -55/5

25 - d^2 = -11

- d^2 = -11-25

-d^2 = -36

d^2 = 6^2

d = 6

Therefore,

required terms are

a+d = 5+6 = 11

a = 5

a-d = 5-6 = -1

( 11, 5, -1 ) or ( -1, 5, 11 )

I hope this helps you.