Question

Calculate the Work done when 1 mole of an ideal gas is compressed reversibly from 1 bar to 4 bar at a constant temperature of 300K.​

Answer 1

Answer:

First and foremost I would like to inform you that work done at constant temperature referred to as isothermal process. Under isothermal process, the internal energy of an ideal gas is constant. That is to say the in the equation of first law of thermodyamics, E=q + w, E=0 hence the equation reduces to q=w

So to calculate compression work done under isothermal process, use the formula w=nRT ln(p2/p1)

= 1 x 8.314 x 300 x ln(5/1)

= 4014.26 J.