Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a
volume of 500 ml to a volume of 2 L at 25°C and normal pressure.
In a constant
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n = 2 moles Vi = 500 ml = 0.5 lit Vf = 2 lit T = 25°C = 298 K w = -2.303 nRT log(VVi)(VVi) w = -2.303 x 2 x 8.314 x 298 x log20.520.5 w = -2.303 x 2 x 8.314 x 298 x log(4) w = -2.303 x 2 x 8.314 x 298 x 0.6021 w = -6871 J w =-6.871 kJ.Read more on Sarthaks.com - https://www.sarthaks.com/931828/calculate-work-done-when-moles-ideal-expands-reversibly-isothermally-from-volume-volume
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