Question

Calculate the work done when a body of mass 100 kg is displaced 10 m distance with the acceleration 5 m/s2. ​

Answer 1

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Explanation:

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Answer 2

Answer:

Given :

Mass (m) = 100 kg

Displacement (s) = 10 m

Acceleration (a) = 5 m/s²

To Find :

Work done (w)

Solution :

As we know that :

$\star \: {\boxed{\rm{F = ma }}}$

$\star \: {\boxed{\rm{W = Fs}}}$

Where :

➞ F = Force

➞ m = mass

➞ a = acceleration

➞ W = Work done

➞ s = Displacement

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Firstly, calculating the force applied by the body with mass 100kg and acceleration 5 m/s².

$\begin{gathered} \qquad\rm{\implies{F = ma }} \\ \\ \qquad\rm{\implies{Force = m \times a }} \\ \\ \qquad\rm{\implies{Force = 100\times 5 }} \\ \\ \qquad\rm{\implies{Force = 500 \: N }} \end{gathered}$

Hence, the Force applied by the body is 500 Newton.

$\rule{300}{1.5}$

Now, calculating the Work done by body with Force 500 N and displacement 10 m.

$\begin{gathered} \quad\rm{\implies{W = Fs }} \\ \\ \quad\rm{\implies{Work \: done = F \times s}} \\ \\ \quad\rm{\implies{Work \: done = 500 \times 10 }} \\ \\ \quad\rm{\implies{Work \: done = 5000 \: J}} \end{gathered}$

Hence, the work done is 5000 Joules.

Learn More :

Velocity

${\longrightarrow{\small{\underline{\boxed{v = u + at}}}}}$

Displacement with positive accelerations

${\longrightarrow{\small{\underline{\boxed{s= ut + \dfrac{1}{2}{at}^{2}}}}}}$

Displacement with negative acceleration

${\longrightarrow{\small{\underline{\boxed{s= ut - \dfrac{1}{2}{at}^{2}}}}}}$

Displacement knowing initial and final speeds

${\longrightarrow{\small{\underline{\boxed{s= \dfrac{1}{2}\big(u + v \big)t}}}}}$

Velocity squared

${\longrightarrow{\small{\underline{\boxed{{v}^{2} = {u}^{2} + 2as}}}}}$

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