Question

calculate the work done when a load of 100kilogram is lifted vertically by 5meter given
(g=10m/a ^2)
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Answer 1

Explanation:

we know that work done (w) = FS cos theta

so here cos theta is -1 since force and displacement are in opposite directions so w= -FS = - mg × s

so w= - 100 kg × 10m/s²× 5m

w= -5000J

Answer 2

FINAL ANSWER:

work done = 4900 J

GIVEN:

m = 100 Kg

h = 5 m

g = 9.8 m/s

TO FIND:

Calculate the work done

FORMULA USED:

Wd = m×h×g

SOLUTION:

Wd = m×h×g

Wd = 100×5×9.8

Wd = 4900 J