Question

Calculate the work expension of two moles of an ideal gas is expanded isothermally and reversibly from 10m3 to 20m3 at 300 k a) 11.4 kj
b) -11.4 kj
c) 0 kj
d) 4.8 kj

Answer 1

Answer:

Given that,

V1=10m³, v2=20m³

n=2 moles

T=300k

Now, work done=-nRTln(v2/V1)

W=-2×8.31×300×ln(2)

On solving u get the solution.......

Explanation:

Hope it helps you frnd......