Question

calculate the work required to be done to stop 1800kg moving at a velocity of 60km/h and also found its speed​

Answer 1

Required total work is equal to the total kinetic energy of the truck.

so we have to covert 60km/h to m/s first

then it will be 60×5/18=150/9m/s

so the K.E =1/2mv^2

1/2×1800kg×(150/9m/s)^2

1/2×1800×150/9×150/9

900×150/9×150/9=500000J or 500KJ

Hence the required work is 500KJ

Answer 2

Answer:

500kJ.........

calculated and gave........

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