calculate the work required to be done to stop a car of 1300 kg moving at a speed of 54 km/h ?
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workdone=1/2mv^2
1/2.(1300.225)
=14625j
1/2.(1300.225)
=14625j
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Work done= change in kinetiic energy
m= 1300 kg
v= 15m/s ( convert 54 km/h into m/s)
Kinetic energy=1/2m(v)2
Kinetic energy = 1/2 ×1300×15×15
Kinetic enegy=14625 j
Work done = 14625 j
m= 1300 kg
v= 15m/s ( convert 54 km/h into m/s)
Kinetic energy=1/2m(v)2
Kinetic energy = 1/2 ×1300×15×15
Kinetic enegy=14625 j
Work done = 14625 j
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