calculate the work required to be done to stop a car of 1500kg moving at a velocity of 60km per hour
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Solution: Kinetic energy, E k= 1/2 mv^2
Where,
Mass of car, m= 1500 kg
Velocity of car, v= 60 km/hr= (60 — 5 )/(18 ms^(-1) )
ˆ´ E k= 1/2 — 1500 — €–(60 — 5/18)€—^2 = 20.8 —€–10€—^4 J
Hence, 20.8 — 104 J of work is required to stop the car.
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Kinetic energy, E k= 1/2 mv^2
Where,
Mass of car, m= 1500 kg
Velocity of car, v= 60 km/hr= (60 — 5 )/(18 ms^(-1) )
ˆ´ E k= 1/2 — 1500 — €–(60 — 5/18)€—^2 = 20.8 —€–10€—^4 J
- Hence, 20.8 — 104 J of work is required to stop the car.
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