factorise the following expression 7a^2-19a-6
Answers
Step-by-step explanation:
= 0
Reorder the terms:
-6 + 19a + 7a2 = 0
Solving
-6 + 19a + 7a2 = 0
Solving for variable 'a'.
Factor a trinomial.
(-3 + -1a)(2 + -7a) = 0
Subproblem 1
Set the factor '(-3 + -1a)' equal to zero and attempt to solve:
Simplifying
-3 + -1a = 0
Solving
-3 + -1a = 0
Move all terms containing a to the left, all other terms to the right.
Add '3' to each side of the equation.
-3 + 3 + -1a = 0 + 3
Combine like terms: -3 + 3 = 0
0 + -1a = 0 + 3
-1a = 0 + 3
Combine like terms: 0 + 3 = 3
-1a = 3
Divide each side by '-1'.
a = -3
Simplifying
a = -3
Subproblem 2
Set the factor '(2 + -7a)' equal to zero and attempt to solve:
Simplifying
2 + -7a = 0
Solving
2 + -7a = 0
Move all terms containing a to the left, all other terms to the right.
Add '-2' to each side of the equation.
2 + -2 + -7a = 0 + -2
Combine like terms: 2 + -2 = 0
0 + -7a = 0 + -2
-7a = 0 + -2
Combine like terms: 0 + -2 = -2
-7a = -2
Divide each side by '-7'.
a = 0.2857142857
Simplifying
a = 0.2857142857
Solution
a = {-3, 0.2857142857}
Answer:
7a^2-19a-6
Grouping
7a^2-19a-6
7a^2+ 2a- 21a- 6
Common factors from the two pair
7a^2+ 2a- 21a- 6
a(7a+ 2) - 3(7a+ 2)
Rewrite in factored form
a(7a + 2) - 3(7a + 2)
(a-3) (7a + 2)
Solution
(a-3) (7a+2)
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