Calculate the work required to be done to stop a car of 1500kg moving at a velocity of 60 km/h.
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change in kinetic energy= amount of Work done
= final K.E - initial K.E
= 1/2(mv2^2) - 1/2(mv1^2)
= 1/2×m(v2^2 - v1^2)
GIVEN:
m= 1500 kg
v1=0
v2 = 60
work done= 1/2×1500{(60×60) - (0×0)}
= 750 × 3600
=2700000 J
I hope it helped
plzzz mark as brainliest....!
= final K.E - initial K.E
= 1/2(mv2^2) - 1/2(mv1^2)
= 1/2×m(v2^2 - v1^2)
GIVEN:
m= 1500 kg
v1=0
v2 = 60
work done= 1/2×1500{(60×60) - (0×0)}
= 750 × 3600
=2700000 J
I hope it helped
plzzz mark as brainliest....!
SARDARshubham:
thanx sanidhya !
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