Calculate the work required to stop the car of 1500 kg moving at a speed of 72 km/h by applying brakes
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m=1500kg
u= 72km/h =72* 5/18 = 20m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 1500{0- (20/3)2}
= -705 j approx
u= 72km/h =72* 5/18 = 20m/s
v =0m/s
w = change in its KE.
initial KE =1/2 mu2
final KE=1/2mv²
w = 1/2mv2 - 1/2 mu2
=1/2m(v2-u2)
= 1/2 * 1500{0- (20/3)2}
= -705 j approx
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