Question

Calculate the work required to stretch a soap film so that its area increases by 4.0 cm2. The surface tension of the air–soap solution interface is 28 mN m−1.​

Answer 1

Answer:

-5

2.4 *10 Joule

Explanation:Physics

Mechanical Properties of Fluids

Surface Tension

Consider a soap film on a r...

PHYSICS

Asked on December 26, 2019 byKarnati Mohandas

Consider a soap film on a rectangular frame of wire of area 4×4cm2. If the area of the soap film is increased to 4×5cm2, the work done in the process will be (The surface tension of the soap film is 3×10−2N/m)

A

12×10−6J

B

2.4×10−5J

C

60×10−6J

D

96×10−6J

MEDIUM

Help best friend

Study later

ANSWER

Consider the problem

Given,

initial area 

A1=4cm×4cm=16cm2=16×10−4m2

Final area 

A2=4cm×5cm=20cm2=20×10−4m2

Surface tension T=3×10−2N/m

Work done