Question

calculate the workdone in increasing the radius of a spherical soap bubble slowly from 1 to 5cm

Answer 1

Explanation:

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Answer 2

$Work \: done \: in \: blowing \: a \: soap \: bubble  \: W \: = \: 2T \: (A2−A1) \\ </p><p> </p><p> now  \: r1 \: = \: 0.05m \:  ,r2=0.1m</p><p></p><p></p><p>So  \: W \: = \: 2T(4πr22−4πr12) \\ =8πT(0.12−0.052) \\ =6.6×10−3J</p><p></p><p>$

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