Question

calculate the zeros of p(x)=x^2 - 2x - 3​

Answer 1

Answer:

x=-1, x=3/2 is a correct answer

Step-by-step explanation:

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Answer 2

Given -

• p(x) = x² - 2x - 3

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To find -

• Zeroes of the polynomial.

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Solution -

We will factorise the given equation by middle term spiliting.

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$\tt\longmapsto{}$ p(x) = x² - 2x - 3

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$\tt\longmapsto{}$ p(x) = x² - 3x + x - 3

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$\tt\longmapsto{}$ p(x) = x(x - 3) + 1(x - 3)

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$\tt\longmapsto{}$ p(x) = (x - 3) (x + 1)

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Fir finding the zeroes, we will put p(x) = 0

$\begin{lgathered}\begin{array}{c|c}\sf x - 3 = 0&\sf x + 1 = 0\\\\\bf x = 3&\bf x = -1 \end{array}\end{lgathered}$

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Hence,

• Zeroes of the given equation are 3 and -1.

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