Question

calculate thr density of h2so4 solution if its molality and molarity are 94.5 and 11.5

Answer 1

Since molarity is no. of moles by by volume in L = 11.5 M  

and molality is no. of moles by weight of solution = 94.5 m 

Therefore on dividing molarity by molality we get the density.

So, density = 11.5/94.5 = 0.121 kg/L

Answer 2

Answer: The density of $H_2SO_4$ solution is 1.22 kg/L

Explanation:

To calculate the density, we use the equation which shows the relationship between molarity, molality and density, which is:

$\frac{1}{m}=\frac{d}{M}-\frac{M_S}{1000}$

where,

m = Molality of the solution (in mol/kg) = 94.5 mol/kg

M = Molality of the solution (in mol/L) = 11.5 mol/L

d = density of the solution

$M_S$ = Molar mass of the solute (in kg/mol)

Mass of $H_2SO_4=[(2\times 1)+32+(4\times 16)]=98g/mol=0.098kg/mol$    (Conversion factor: 1 kg = 1000 g)

Putting values in above equation, we get:

$\frac{1}{94.5}=\frac{d}{11.5}-\frac{0.098}{1000}\\\\d=1.22kg/L$

Hence, the density of $H_2SO_4$ solution is 1.22 kg/L