I want the solution of question 21 all parts... please help as fast as possible...
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Hi friend,
1) since two resistors are in parallel,
Effective resistance= R1+R2
R= 8+8
R= 16 ohm.
2)according to ohm's law,
V= IR
I= V/R
I=8/4
I= 2A
3)v= ir
V= 2×4
V= 8V
4)power(P)= I²R
P= 2²×4
P= 16W
5)I think there is ammeter difference in reading as the both resistors having different current.
I=2-1
I= 1A
Hope this helped you a little!!!
1) since two resistors are in parallel,
Effective resistance= R1+R2
R= 8+8
R= 16 ohm.
2)according to ohm's law,
V= IR
I= V/R
I=8/4
I= 2A
3)v= ir
V= 2×4
V= 8V
4)power(P)= I²R
P= 2²×4
P= 16W
5)I think there is ammeter difference in reading as the both resistors having different current.
I=2-1
I= 1A
Hope this helped you a little!!!
Anonymous:
thanks @saka
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