calculate thr ratio of mean square speed of molecules of a gas at 60 K and 240 K
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Answer:
C1C2=√T1T2=√24060=√4=2 .
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Answer:
Data: T1=30K,T2=120K
The mean square speed, v−2=M03RT
∴v2−2v1−2=T2T1 for a given gas
∴v2−2v1−2=120K30K=41 for a given gas
This is the required ratio
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