Question

calculate time period of a simple pendulum of length 256cm in moon (g=1.6ms-² pie=3.14). Also explain how time period is affected if it takes to moon
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Answer 1

Answer:

See the attachment........

Answer 2

YOUR ANSWER IS HERE..

$t \: = 2\pi \: \sqrt{ \frac{l}{g} }$

l = 256 cm

100 cm = 1 m

so, 1 m = 256 = 2.56 m

100

g = 1.6 ms -²

$2\pi \: \sqrt{ \frac{2.56}{1.6} } \\ 2\pi \: \sqrt{ \frac{25.6}{16} } \\ 2\pi \: \sqrt{ \frac{1.6}{4} }$

$2 \times \frac{22}{7} \times \frac{1.6}{4} \\ \frac{176}{35} \\ 5.023$

I HOPE THIS WILL HELP YOU..