Question

Calculate tje no. Of molecular of sulphir present in 16 g of solod sulphur

Answer 1

Calculate - (a) The number of molecules of sulphur (S8) in 16 g of solid sulphur. (b) Number of moles in 20 g of water. Therefore, 16 g of S8 contains 3.76 x 1022 molecules.

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 16g of solid sulpur contains

(6.022×10^23 /256 )16 molecules

= 3.76 × 10^22 molecules (approx)

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I hope, this will help you.☺

Thank you______❤

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