Question

Calculate tje volume of 1 mole of a gas at exactly 20° c at a pressure of 101.325 kpa

Answer 1

Answer:

The volume of 1 mole of gas is 24.055 L.

Explanation:

Given data:

No. of moles of gas, n = 1

Absolute temperature, T = 20° C = 20 + 273.15 K = 293.15 K

Pressure, P = 101.35 kPa = 101.35 * 10³ Pa = 101.35 * 10³ * 9.869*10⁻⁶ = 1 atm ......  [ ∵ 1 Pa = 9.869 * 10⁻⁶ atm]

To find: Volume, V

Using the Ideal Gas Law, we get

PV = nRT

Where, R = ideal gas constant = 0.08206 L. atm. mol−1

V = n(RT/V)

Or, V = 1 * [(0.08206 * 293.15) / 1] = 24.055 L