Calculate total moles after dissociation in 0.1M KCl solution and 0.05M aluminium sulphate solution. Hence,
decide which of the two solutions will have higher freezing point depression.
Answers
Explanation:
Freezing point depression is higher in Al2(SO4) 3
Answer:Total no of moles after dissociation of 0.1M KCl will be 0.2 M and for 0.05 M aluminium sulphate solution it will be 0.25 M.
Aluminium Sulphate will show greater depression in freezing point.
Explanation: As we know that KCl will be dissociated into 1 mole of K+ and 1 mole of Cl- , so total number of moles will be 0.1 + 0.1 = 0.2 M
In case of aluminium sulphate it will be dissociated into 2 Al3+ ions and 3 SO42- ions.
Therefore total number of moles after dissociation will be ( 2x0.05 + 3x0.05) = 0.25 M
Now, as per the Roult's Law the depression in freezing point will be directly proportional to the Vant Hoff factor (i) , when other parameters remains constant.
After dissociation KCl produces only 2 ions and aluminium sulphate produces 5 ions. As i value of aluminium sulphate is higher than that of KCl , so it will show higher freezing point depression.
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