Question

Calculate total number of atoms (In terms of NA) present in 34 g of NH3. Where NA is Avogadro's number.

Answer 1

Explanation:

17g of NH3.= 6.02×10^23

34 g of NH3.= (6.02×10^23×34) / 17

= 1.204 × 10^24

Answer 2

Answer:

2*6.022*10power 23

12.044*10 power 23

Explanation:

1mol =6.022*10 power 23

34 g of NH3 =2 mol

So 34 g of NH3 = 2 NA