Question

Calculate total number of atoms present in 9gm of water?

Answer 1

Answer:

3.011*10 to the power of 23

Explanation:

18 grams of water contains 6.022*10 to the power of 23 so 9grms of water would contain 3.011*10 to the power 23

Answer 2

Total atoms is $9.033 x 10^2^3$

Explanation:

1. 9 is $\frac{1}{2}$ of 18, meaning that $\frac{1}{2}$ mole is present in 9 g of water.  

2. $1/2 \times 6.022 \times 10^2^3 = 3.011 \times 10^2^3$ molecules $H_2O$.  

3. However, if you want to know how many ATOMS are present in $3.011 \times 10^2^3$,  

4. we must then multiply by 3  (2 hydrogen atoms and 1 oxygen atom per molecule),  

and get $9.033 * 10^2^3$ atoms.