calculate total number of ion in 0.585 gram of sodium chloride (Nacl)
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23+ 35.5=58.5 - 6.023*10^23
so 0.585- ?
x= 0.585*6.023*10^23÷58.5
x= 0.06023*10^23=60.23*10^20
so 0.585- ?
x= 0.585*6.023*10^23÷58.5
x= 0.06023*10^23=60.23*10^20
Saurabh1423:
i hope u understood
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