Calculate total number of optical isomers in following compound:

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Explanation:
Hence, we have derived that, if 'n' (number of chiral centers) is odd for a compound with similar ends, then:
Number of meso isomers=2(n−1)/2.
Total number of optical isomers=2n−1.
Number of enantiomers=2n−1−2(n−1)/2.
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