Calculate total number of valence electrons present in 1.42gm of methane.
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Answer:
4.239×10^23
Explanation:
no.of mol of methane = 1.42/16 = .0.088
no.of molecules of methane = 0.088×6.022×10^23
1 molecule of methane contains 8 Valence electrons
hence , no of Valence electrons =
= 0.088×6.022×10^23×8
= 4.239 ×10^23
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