Question

Calculate vapour density of a sample containing 5 mole of O2 and 5 mole of N2 with respect to He

Answer 1

$\huge\boxed{ \mathbb\red{❥A} \green{n} \mathbb\blue{S} \purple{w} \mathbb \orange{E} \pink{r}} \:</p><p>$

▪️O2=5×32=150

▪️N2=5×28=140

▪️vapour density=150+140/4

▪️(V.D)=290/4

▪️(V.D)=72.5

Answer 2

Answer:

▪️O2=5×32=150.

▪️O2=5×32=150.▪️N2=5×28=140.

▪️O2=5×32=150.▪️N2=5×28=140.▪️vapour density=150+140/4.

▪️O2=5×32=150.▪️N2=5×28=140.▪️vapour density=150+140/4.▪️(V.D)=290/4.

▪️O2=5×32=150.▪️N2=5×28=140.▪️vapour density=150+140/4.▪️(V.D)=290/4.▪️(V.D)=72.5.