Question

calculate volume in litre of semi - molar NAOH solution required to neutralize 200 ml of decimolar H2SO4 solution.​

Answer 1

Answer:

20 ml

Explanation:

We know that :

N

1

V

1

=N

2

V

2

Normality=Molarity×Basicity

For sulphuric acid, the basicity is 2.

∴N

1

=0.1×2=0.2N

V

1

= ?

N

2

=0.1×1=0.1N

V

2

=40ml

0.2×V

1

=0.1×40

V

1

=20ml

Answer 2

Answer:

20ml

Explanation:

we know that

29ml 24ml