Question

calculate volume occupied by 6.022*10^23 molecule of o2

Answer 1

Given Molecules of o2 = 6.22*10^23

we know that:-

Number of Moles is equal to :-

$=\dfrac{Number\:of\:molecules\:given}{N_A}$

$\rule{200}{2}$

Number of moles of Oxygen given :-

$=\dfrac{6.022*10^{23}}{6.022*10^{23}}\\ \\ \\ \\=1$

$\rule{200}{2}$

Again we know  that

$Moles=\dfrac{volume\:given}{22.4}$

$\rule{200}{2}$

Thus,

Volume occupied by 1 mole of Oxygen will be :-

$mole=\dfrac{volume\:occupied}{22.4}\\ \\ \\ \\volume\:occupied=mole*22.4\\ \\ \\ \\volume=1*22.4\\ \\ \\volume=22.4\:Litres$

$\rule{200}{2}$