Calculate volume of o2 formed at STP when 2 moles of MnO2, react with 2 moles of H2O2 in excess of H2SO4, as per following reaction
MNO2+H2O2--->MNSO4+2H2O+O2
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Answered by
1
Explanation:
2h² o²= 2h202
2 mol 1 mol
= 2 × 34 = 68 g 22400 ml
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Answer:
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