Question

the position vector of an object at any time t is given by 3tsquareicap+6tjcap+kcap.otsbvelocity along y axis has the magnitudes​

Answer 1

Answer:

x = 3t² i + 6t j + 1.k

differentiate with respect to time

dx/dt = 6t i + 6j + 0k

we know , dx/dt = velocity

so,

v = 6t i + 6 j + 0.k

hence , velocity along x -axis = 6t

velocity along y-axis = 6

and velocity along z-axis = 0

hence, velocity along y -axis = 6 unit

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