Question

calculate wavelength of photon emmitted from second line of balmar series from hydrogen​

Answer 1

Answer:

We know wavenumber = Rh (1/n1²-1/n2²) z2

For balmer series second line n1=2 and n2= 4

By putting in formula we get

Rh (1/4- 1/16)

Rh( 3/16)

Rh=109678

There wavenumber no. = 329034/16

And wavelength= 16/329034 = 4.86 × 10^ -5