Question

what is the smallest no. which when increased by 3 is exactly divisible by 27, 35, 39, and 42?​

Answer 1

Answer:

Step-by-step explanation:

Prime factorization of numbers

27 = 3^3

35 = 5*7

25 = 5^2

21 = 3*7

Smallest number divisble by above 4 numbers will be LCM = 3^3 * 5^2 * 7 = 4725

Now , the number we need is 3 less than 4725 , therefore the number is 4722