Calculate wavelength of the second line of Lyman series in hydrogen spectre
Answers
Answered by
0
1/ λ = R[1/n₁² - 1/n₂²]
For second line of Lyman series
n₁ = 1 and n₂ = 3
1/λ = R[1/1² - 1/3²]
= 8R/9
λ = 9 / (8R)
= 9 / (8 × 1.097 × 10^7 m^1)
= 102.5 nm
∴ Wavelength of second line of Lyman series is 102.5 nm
Similar questions