Question

Calculate weight of iron which will be converted into its oxide(Fe3O4) by action of 18g steam on it.

Answer 1

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Answer 2

Answer:42 g

Explanation: moles of steam $(H_2O)=\frac{\text{ given mass}}{\text{ molar mass}}$

moles of steam $(H_2O)$=\frac{18g}{18g/mol}=1 mole[/tex]

$3Fe+4H_2O\rightarrow Fe_3O_4+4H_2$

From the balanced equation:

4 moles of steam react with =3 moles of iron to give ferric oxide.

1 mole of steam react with =$\frac{3}{4}\times 1=0.75moles$ of iron to give ferric oxide.

Mass of iron=$moles\times {\text {molar mass}}=0.75\times 56g/mol=42g$