Question

calculate work done during the reaction of thermochemical equation at 300K
CH4(g)+2O2(g) -- CO2(g)+2H2O(l).
R=8.314jk _1 mol_1

Answer 1

Answer:

+4.988kJ

Explanation:

Ch4+2o2=co2+h2o

Ch4 co2 and o2 are in gaseous state so

Delta ng ie no of moles of gaseous product-no of moles of gaseous reactant

=1-3=-2

W=delta ng RT

W=-2×8.314.300

W=4988 J

W=+4.988kJ