calculate x-1/x when x²+1/x²=27.
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2
x² + 1/x² = 27
=> (x - 1/x)² = x² + (1/x)² - 2(x)(1/x)
(x - 1/x)² = x² + 1/x² - 2
(x - 1/x)² = 27 - 2
(x - 1/x)² = 25
x - 1/x = √25
x - 1/x = 5
=> (x - 1/x)² = x² + (1/x)² - 2(x)(1/x)
(x - 1/x)² = x² + 1/x² - 2
(x - 1/x)² = 27 - 2
(x - 1/x)² = 25
x - 1/x = √25
x - 1/x = 5
Answered by
0
x-1/x equals y
x sq +1/xsq -2=25
x-1/x=5
x sq +1/xsq -2=25
x-1/x=5
varsha311:
its just simple
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