calculated the mass of sodium cloried required to prepare it 20% solution in 100 gram of water.
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Let the mass of sodium sulphate required be = x g
The mass of solution would be = (x +100) g
x g of solute in (x + 100) g of solution
20% = ×/x+100 x100
20 x + 2000= 100 x
80 x = 2000
x = 2000/ 80
= 25 g
The mass of solution would be = (x +100) g
x g of solute in (x + 100) g of solution
20% = ×/x+100 x100
20 x + 2000= 100 x
80 x = 2000
x = 2000/ 80
= 25 g
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